knashha2007-06-07T17:40:30Z
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One simple way is reduce mod 11:
79z = r = 2z mod11, z = 6r mod 11 so set z = 11s + 6r
Put this value into the equation and divide by 11 to get,
3x + 5y - 9w = -43r-79s. (this is the "new" r value). Let's reduce mod3 to get
5y = -r -s mod3, 2y = -r-s mod3, so y = r + s mod 3 and we
can write,
y = 3t + r + s. Plug this in and divide by 3 to get.
x - 3w = -5t - 16 r - 28s and reduce mod 3
x = t - r - s mod3 so we introduce a new variable u and,
x = 3u + t - r - s. Plug in and divide by 3 and solve for w
w = u + 2t + 9s + r, together with the values,
x = 3u + t - r - s
y = 3t + r + s
z = 11s + 6r
provide a parametric solution to your equation.
psbhowmick2007-06-07T21:34:48Z
the question is incomplete.... more information is reqd. about s, t, u