who knows how to do this probability question?
Five women and two men are being interviewed for a job opening. Find the probability that all the women will be interviewed first.
Five women and two men are being interviewed for a job opening. Find the probability that all the women will be interviewed first.
JimmyJo
Favorite Answer
Probability is 1/42
Odds are 1:41
Anonymous
5/7 * 4/6 * 3/5 * 2/4 * 1/3
petitericeball
So there are 7 people applying and two of them are women. the first woman has a 1/7 chance, the second would have a 1/6 chance, so I'd say a 42:1 chance.
Jun Agruda
= 100%(5/7 * 4/6 * 3/5 * 2/4 * 1/3)
= 100%(5/7 * 2/3 * 3/5 * 1/2 * 1/3)
= 100%(30/630)
= 100%(1/21)
= 100/21% or 4 16/21% or 4.76 4/21%
Answer: 1/21 or 4.76 4/21% or 1:20 ratio