math help please????????????????

how do you find the square root of 24 and the square root of 26?
for example the square root of 32 is 4sqrt2(4 then the square root symbol then 2 inside that symbol) please explain..i really need help
10 points:)
thank you

2009-08-30T10:55:26Z

Favorite Answer

√24= √4 * √6= 2√6

√26= √26 because no perfect squares can go into it

?2009-08-30T17:47:54Z

Its easy. First you take the big number in the square root like √50. then you break down that 50 into its smallest factors like 2x5x5. Those numbers cant be broken down anymore. Then you find any pair of two same numbers so the 5 has two fives. Simply bring out a 5 so the final answer would look like 5√2. The 2 inside the square root didnt have any pairs so it stays inside. If there were two numbers inside without a pair such as a 2 and maybe a 7 then you would multiply those together to get 14 inside the square root symbol.

?2009-08-30T17:59:35Z

First break down the numbers.
24 = 2 * 2 * 2 * 3
26 = 13 * 2

Since it is Square root... For every two same numbers inside the square root symbol, remove both of them and instead, put one of the numbers outside the square root.
√24 = √(2 * 2 * 2 * 3) = 2√(2 * 3) = 2√6
Therefore √24 = 2√6

Similarly,
√26 = √(13 * 2)
= √26 (It cannot be simplified further. So it is left as it is)

Ad astra2009-08-30T17:42:31Z

24 is 6*4 = 2^2 * 3*2

2√(6)

26 = 13*2 =√26


So a number like 18 is equal to 9*2
9 is 3 squared.
so 3^3 * 2
3√2

Cdog2009-08-30T17:43:01Z

sqrt(24) = 2(times the sqr root of )(6)

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