How to pass a 2D array to another function in C++?

Question

Here the code void results() { double storeScores; for (int ii = 0; ii < NUM_ROWS; ii++) { cout << "Please enter 9 Numbers that you want to input for group" << ii + 1 << endl; for (int jj = 0; jj < NUM_COLS; jj++) { cout << jj + 1 << " | "; cin >> storeScores; scores[ii][jj] = checkInput(storeScores); } } } double checkInput(double aScores){ if(aScores > 20 || aScores < 0){ cout << "Invalid value! Enter score again:" << endl; cin >> aScores; } return aScores; } void printscores() { cout << " " <

? · Accepted Answer

Here is how you can create and initialize your double ** on the heap. Use i.e. double **scores = GetDouble(NUM_ROWS, NUM_COLS) to create your array. The following prototype declares a parameter of your array:  double fct(double **d). I hope that helps.

double **GetDouble(int iRows, int iCols)
    {
    double **dbl = new double*[iRows];
    for (int i = 0; i < iRows; i++){
        dbl = new double[iCols];
        for (int j = 0; j < iCols; j++){
            dbl[i][j]=0.0f;
            }
        }
    return dbl;
    }

Paul · Answer

Change:

void printscores()

to:

void printscores(double scores[NUW_ROWS][NUM_COLS])

mpchatty · Answer

Pass a pointer to the 2nd method. :)

How to pass a 2D array to another function in C++?

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