How to calculate these algebra equations?
4 * (2/3)
Like I've tried doing it this way... 4/1 * 3/2 = 8/2 * 3/2 = 11/2 is that correct?
A similar one would be (1/3) - 4 * (9/2)
4 * (2/3)
Like I've tried doing it this way... 4/1 * 3/2 = 8/2 * 3/2 = 11/2 is that correct?
A similar one would be (1/3) - 4 * (9/2)
Anonymous
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I'm assuming the * is indicating multiplication, not raising the value to a certain power.
When you multiply fractions, you literally just multiply across. That's it. Nothing fancy.
(4/1) * (2/3)
4 is the numerator in the first value and 2 is the numerator in the second value. Those two values multiplied together equal 8. 1 is the denominator in the first value and 3 is the denominator in the second value. Those two values multiplied together equal 3. Therefore, the answer to the problem is 8/3.
If the * is indicating raising the 4 to the value of (2/3), you must think of things in terms of radicals. sqroot2 is the same as 2^(1/2). That's just how things are. 4^(2/3) is therefore the same as (cuberoot4)^2.