Tully-Fisher relation?
The Tully Fisher relation can Be used to find the Distances to galaxies.
Tully Fisher relation: L= V^4
L is the luminosity
V is the rotational velocity of the galaxy in km/s
I went online and did a little research and found out that You can express the Luminosity as the Absolute magnitude. I actually found 2 equations:
M = 4.8 - 2.5 x log(L/Lsun)
or
M= -9.5 x log(Rotational velocity in km/s)+2
Where M is the Absolute magnitude
I tried to test these equations On the Andromeda Galaxy. Since I couldn't find the rotation curve Of Andromeda, I couldn't use the second equation.
Luminosity of Andromeda = 2.6 x 10^10 L_sun
M= 4.8-2.5 x log(2.6 x 10^10)
M= -21.23 <---- absolute magnitude of Andromeda.
I wanted to test If I my answer was right. So used this absolute magnitude and the apparent magnitude of Andromeda, 3.44, to find its distance, which I already know is 2,540,000 Light years.
Distance= 3.44-(-21.23)+5)/5)
Distance= 10^5.934= 859,013.522 parsecs
859,013.522 parsecs = 2,801,789.65 light years
Is that a close enough answer, or am I just using the Wrong Equation to find the Absolute Magnitude.
And since L= V^4
(2.6 x 10^10)^(1/4) = 401.55 km/s is the Rotation curve for Andromeda Right?
I just want to know the real equation and if my answers are valid.