Solid chromium (III) hydroxide reacts with nitric acid. Write the balanced net ionic equation.?

Cr(OH)3(s) + 3HNO3(aq) --> Cr(NO3)3(aq) + 3H2O(l)
This is the correct balanced chemical equation.

I have tried entering both:
3OH-(aq) + 3H+(aq) --> 3H2O(l)
3OH-(s) + 3H+(aq) --> 3H2O(l)

But neither are marked correct. Could someone please tell me what is wrong with my answer?

2010-09-21T13:38:41Z

OH-(s) + H+(aq) --> H2O(l)
OH-(aq) + H+(aq) --> H2O(l)
Are also incorrect

2010-09-21T13:43:00Z

Cr(OH)3(s) + 3H+(aq) --> 3H2O(l) + Cr{3+}(aq)
Is apparently the answer... can someone explain why? The Chromium doesn't have a change in charge.

AK2010-09-21T13:45:47Z

Favorite Answer

You cannot take a solid apart. The solid has to be together.
You have to keep the solid and then take out the spectator ions,which would be nitric acid.

Cr(OH)3 (s)+ 3H+ (aq) --> Cr3+ (aq) +3H2O

?2016-10-04T06:20:27Z

Chromium Iii Hydroxide

Pebrook2015-08-19T05:35:47Z

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RE:
Solid chromium (III) hydroxide reacts with nitric acid. Write the balanced net ionic equation.?
Cr(OH)3(s) + 3HNO3(aq) --> Cr(NO3)3(aq) + 3H2O(l)
This is the correct balanced chemical equation.

I have tried entering both:
3OH-(aq) + 3H+(aq) --> 3H2O(l)
3OH-(s) + 3H+(aq) --> 3H2O(l)

But neither are marked correct. Could someone please tell me what is wrong with my answer?

Anonymous2016-03-20T02:55:57Z

(b) Solid chromium (III) hydroxide reacts with nitrous acid. Cr(OH)3 (s) + 3HNO3(aq) → Cr(NO3)3(aq) + 3H20(l) Cr(OH)3(s) + 3H(+)(aq) + 3NO3(-)(aq) → Cr(+3)(aq) + 3NO3(-)(aq) + 3H2O(l) Cr(OH)3(s) + 3 H(+)(aq) → Cr(3+)(aq) + 3H2O(l)

Anonymous2014-10-07T20:51:46Z

Cr(OH)3(s)+3HNO2(aq)→Cr3+(aq)+3NO2−(aq)+3H2O(l)

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