What do they look for when they ask?

Solve for B when A= 1/B+C

ben e2010-10-15T17:27:02Z

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They are looking for an equivalent equation like B = ??????????.

For A= 1/B+C,
A - C = 1/B
1/(A - C) = B
B = 1/(A - C)


If you happened to mean A= 1/(B+C) instead,

B + C = 1/A
B = 1/A - C = (1 - AC)/A