Three objects of uniform density- a solid sphere, a solid cylinder, and a hollow cylinder- are placed at?

Three objects of uniform density- a solid sphere, a solid cylinder, and a hollow cylinder- are placed at the top of an incline. They are all released from rest at the same elevation and roll without slipping. Which object reaches the bottom first? Which reaches it last? Try this at home and note that the result is independent of the masses and the radii of the objects.

Anonymous2010-11-14T07:19:52Z

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momen inertia of (each object is solid)

I_sphere = (2/5)mr²

I_cylinder = (1/2)mr²

I_thin_cylinder = mr²


torque = I α

(friction) r = I (a/r)

friction = Ia/r²

second Newton's law of linear motion,

ΣF = m a

m g sin θ - friction = m a

m g sin θ - Ia/r² = m a

m g sin θ = (m + I/r²)a

a = m g sin θ/(m + I/r²)


a ∼ 1/I

acceleration inversely proportional with respect to the moment of inertia,

I_sphere < I_cylinder < I_thin_cylinder

The sphere reaches the bottom for the first time and thin_cylinder for the last one.







'Try this at home and note that the result is independent of the masses and the radii of the objects.'

moment of inertia I = kmr²
hence k is a real constant.

a = m g sin θ/(m + I/r²)

a = m g sin θ/(m + kmr²/r²)

a = g sin θ/(1 + k)

acceleration a is independent of the masses and the radii of the objects.

Physicsquest2010-11-14T07:07:49Z

1st = solid sphere

2nd = solid cylinder

3rd = hollow cylinder