The kinetic energy of an electron in a particular Bohr orbit of hydrogen is 1.35x10^ - 19 Joules.
Suppose the electron moves away from the nucleus to the next higher Bohr orbit. Calculate the kinetic energy of the electron in the orbit now in eV.
DH
Favorite Answer
K = m*e^4/(εo^2*8*n^2*h^2)
so n = sqrt((m*e^4)/(K*εo^2*8*h^2) =
sqrt((9.11x10^-31*(1.60x10^-19)^4)/(1.35x10^-19*(8.854x10^-12)^2*8*(6.63x10^-34)^2) = 4
so for n = 5
K = m*e^4/(εo^2*8*n^2*h^2) = 9.11x10^-31*(1.60x10^-19)^4/((8.854x10^-12)^2*8*5^2*(6.63x10^-34)^2) =
= 8.66x10^-20J = 0.543eV