a. hydrochloric acid and sodium chloride
b. potassium hydroxide and sodium hydroxide
c. potassium hydroxide and potassium chloride
d. ammonia and ammonium chloride
e. ammonia and water
please answer and explain if you can! thank you.
lamp
this is NaCl and HCl, because of the fact there is not any way that they could be mixed to variety the two a susceptible acid/conjugate base or susceptible base/conjugate acid pair. consistent with the previous respond, RbOH and HF can variety a buffer. If there is extra HF than RbOH, then the hydroxides will pull the H+ of each and every of the HF it may, forming water and F-. the the remainder of the HF will stay linked. for that reason, you have HF (a susceptible acid) and F- (a conjugate base) in answer.
Anonymous
D. as a weak acid and weak base pair is present, Nh3 a weak base and Nh4+ a weak acid
This can be prove as the formula by the following equation for ph
ph= pka + log([weak base]/[weak acid]
Rupal
none of these...
they are the pair of Strong Base n its salt with weak acid...or other way round that is Strong Acid and its salt with weak base.....