A solution is prepared from 42.0 g of a nonvolatile, nondissociating solute and 85.0 g of water.?

The vapor pressure of the solution at 60degree C is 142 torr. The vapor pressure of water at 60degree C is 150. torr. What is the molar mass of the solute? Ignoring the significant figures for this problem.

?2011-09-23T11:40:47Z

Favorite Answer

Pv solution = mole fraction water x vapor pressure water
142torr = (1-x)(150)
0.946 = x = mole fraction of water
therefore, the mole fraction of the solute = 0.053

moles water = 85g / 18g/mole = 4.72moles = 94.6% of the solution
4.72moles / 0.946 = 4.99moles total in the solution
4.99moles - 4.72moles = 0.272moles solute
42g / 0.272moles = 154.5g/mole

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