2.287g of a metallic oxide is reduced with excess H, 1.054g of the metal is produced. Find the metallic oxide.?

Question

? · Accepted Answer

mass of metal = 1.054 g 
mass of metal oxide = 1.187g
mass of O = 1.187 - 1.054 = 0.133 g or .133 / 16 moles of O = 0.008313  moles

If the metal oxide is M2O the moles of M = 0.008313 x 2 moles
molar mass of M = 1.054/ 0.01663
 
= 63.40 g / mol .. copper

it helps if you give the correct data

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