Integral from x to 2x of e^(xt) dt....can't figure this out, is it a double integral?

2012-11-12T18:52:21Z

Yeah, what did you do there, why did you divide by x?

ted s2012-11-12T18:46:51Z

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NO , f(x) = int over tin [ x , 2x ] of { e^xt) dt } = [ e^(xt) / x ] | x to 2x = [ e^(2x²) - e^(x²) ] / x = f(x)

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