synthetic division algebra question?

Solve using synthetic division to divide the first polynomial by the second
1.)

x^4+9x^3+6x^2-65x-63, x-7

2.) 5x^3-18x+3, x+1

Pi R Squared2013-04-01T11:20:01Z

Favorite Answer

Hi,

1.)
x^4+9x^3+6x^2-65x-63, x-7

. __________________
7)1 . 9 . . 6 . -65 . .-63
. __ 7_112_826_5327_
. 1 16. 118 761. 5264

x³ + 16x² + 118x + 761 + 5264/(x - 7) <==ANSWER



2.) 5x^3-18x+3, x+1
. _____________
-1)5 . 0 . -18 . 3
. __ -5___5_13__
. . 5. -5 . -13 10

5x² - 5x - 13 + 10/(x + 1) <==ANSWER

I hope that helps!! :-)

pgd_malaka2013-04-01T11:23:59Z

7 l 1 9 6 -65 -63

1 16 118 761 5264 (answer line)

So, x^3 + 16x^2 + 118x + 761 R5264



1 l 5 0 -18 3

5 5 -13 -10


So, 5x^2 + 5x - 13 R -10

musa a2013-04-01T11:18:42Z

1) 16 x^3 + 6 x^2 - 65 x - 63
2) -5 x^2 - 16 x +3

Anonymous2016-11-01T17:22:13Z

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Let'squestion2013-04-01T11:47:18Z

1)(x^4+9x^3+6x^2-65x-63)/(x-7)or
]x^4+9x^3+6x^2-65x-63[x³ + 16x²+118x + 761
-(x⁴-7x³)
-----------
16x³+6x²
-(16x² -112x²)
----------------
118x² -65x
-(118x² -826x)
------------------
761x - 63
-( 761x - 5327)
-----------------------
5264
So the remainder is 5264

2.) (5x³-18x+3)/(x+1)
]5x³-18x+3[5x² -5x -13
-(5x³+5x²)
--------------
-5x²-18x
-(-5x² -5x)
---------------
-13x +3
-(-13x -13)
--------------
16
So 16 is the remainder