mecdub
Favorite Answer
a. Let x be the cost per square foot and y be the cost of the lot.
3000x + y = 373,000
-(4000x + y = 483,000)
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-1000x = -110,000
x = $110/ft²
y = $43,000
b. The cost of the lot and the price per square foot are constant, no matter what size the house is, so letting P be price and s be size,
P = 110s + 43,000
c. Use the equation from b.
1,000,000 = 110s + 43,000
s = 8,700 ft²
d. The domain is the size. [2,000, 8,700), or 2,000 ≤ s < 8700.
The range is the price. Find the price associated with 2,000 ft².
P = 110(2,000) + 43,000 = $263,000
The range is [263,000, 1,000,000), or 263,000 ≤ P < 1,000,000.
e. For the graph, plot an open circle at (8700, 1,000,000) and a closed circle at (2,000, 263,000). Draw a straight line between those two points.
Sakaria
a.(483000-373000)/(4000-3000)
=110$per square feet
b. y=110x+b
=373000=110(3000)+b
=373000=330000+b
=b=373000-330000
=b=43000
y=110x+43000
c. 1,000,000=110x+43000
110x= 1000000-43000
110x=957000
x=8700 feet square
d. domains 2000>x>0 range 263000>y>43000