hippie_slay
Cl-Bz + CH3COCl/AlCl3 ----> Cl-Bz-COCH3 + DIBAL-H/H2O ---> Cl-Bz-CHO
-First step Friedel crafts acylation to get ketone group on opp. side of Cl
-Second step use DIBAL-H, a special reducing agent that reduces esters, carb. acids, and ketones to an aldehyde...Or, you could have used LiAlH4, H2O, then PCC.
-This makes p-cl-bz-ald
Merry christmas.