A .1M solution of acetic acid (Ka=1.8x10^-5) is titrated with .1m solution of naoh.What is the pH when 50% of the acid has been neutralized?

Gervald F2014-03-26T14:16:50Z

Favorite Answer

pH = pKa at this point. Just take the negative log of the Ka value that you have quoted.

Jan2014-03-26T21:28:54Z

pH = 4.74