If you pour a cup of coffee that is 200 F, and set it on desk in a room that is 68 F, and 10 minutes later it is 145 F,...?
If you pour a cup of coffee that is 200 F, and set it on desk in a room that is 68 F, and 10 minutes later it is 145 F, what temperature will it be 15 minutes after you originally poured it?
If t=0, P = 200
\[P_{t} = 132e^{-kt}+68\]
\[145 = 132e^{-10k}+68\]
\[\rightarrow k = 0.0539\]
\[P_{15} = 132e^{-.0539*15}+68\]
\[P_{15} = 126.81\]
so its 127??
Did I do it correctly? If not, please help me!