Example #1:
A car with an initial speed of 6.5 m/s accelerates at a uniform rate of .92 m/s(squared) for 3.6s. Find the speed and the displacement of the car during this time.
Explain everything. Assume I'm a babby or a brit twit.
Andrew Smith
two kinematics formulae are used here.
1. s = ut + 1/2 a t^2
u = initial velocity = 6.5 m/s
a = acceleration = 0.92 m/s^2
t = time = 3.6 s
s is the pronumeral used for displacement.
Substitute to get the answer.
Note that you should not use the term SPEED.
Speed has a different meaning and can only be used if the conditions constrain its motion.
For the above equation to work you MUST be moving in a single direction only. ie along a straight line path.
The velocity ( v)
v = u + at
= 6.5 + 0.92 * 3.6