What is the sum of the degree measures of the interior angles of a regular octagon?

Anonymous2015-11-08T15:00:53Z

What is the sum of the degree measures of the interior angles of a regular octagon?


Apply this formula for sum of degree measures of interior angles of a polygon: S = 180° (n - 2)...where 'n' is the number of sides...an octagon has 8 sides so we substitute 8 for n and evaluate..

S = 180° (8 - 2)
S = 180° (6)
S = 1080° <--- answer...

Philip2015-11-08T15:28:14Z

One side of a regular n-gon subtends angle 2pi/n at the circle center upon
which it may be superimposed. The the angle between adjoining sides of a
regular n-gon is pi -2pi/n = (n-2)(pi/n). There are n such adjoining angles in
the n-gon totaling (n-2)pi radians. For an octagon n = 8 and the sum of the
interior angles is 6pi rad. or 1080 degrees.

alex2015-11-08T14:57:41Z

1080