Let x be a real number. Prove that if |x-1|<1, then |x^2-4x+3|<3?

xyzzy2016-01-20T20:56:59Z

|x^2-4x+3|
| (x-3)(x-1)|
| x-3 | |x-1|
|x-1| < 1
0<x< 2
-3<x-3<-1
1<|x-3|<3

| x-3 | |x-1| < |x-3| < 3

00

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