4 part Physics Help Please?

A) Use the equation ω=∆θ/∆t to find the angular speed. θ=2π and t=24 hrs/3600s (because you have to convert to seconds for rad/s). If you plug the numbers in you get 2π/(24÷3600s)=7.3x10^(-5) rad/s

B) ω is positive for counter-clockwise rotation and negative in the clockwise direction. From the north pole, you see that the Earth rotates counter-clockwise, so ω is positive.

C) For this, we are looking at the tangential velocity. The equation for this is v_t=rω. As given, we know that r=6.37×10^6 m. We also know ω from A. Plug those in to get v_t=(6.37×10^6 m)(7.3x10^(-5) rad/s) = 463 m/s

D) The angular difference between the equator and the north pole is 90º. 3/5 of that would be 54º. Using rules for trig, you can find that the radius at that point is r=(Earth's radius)cos54º=3.74x10^6. Then you plug that into the v_t=rω equation again to get v_t=(3.74x10^6)(7.3x10^(-5) rad/s)=272 m/s
*I had a different angle for this, so check with you calculator to make sure I didn't make any errors.

Hope that helps....Show more