def printme(str):
print("Hello")
printme()
I am getting a IndentationError: expected an indented block error, I am trying to see if I simply type the variable will it return the
variables defined commands. Can someone explain this to me
This is a python question
husoski
Favorite Answer
Your "def" statement begins a function definition. The statement that that make up the function (describe what's done when the function is executed) immediately follow the def statement and *must be indented*.
Python uses indentation instead of symbols or words, to group lines. So try this:
def printme(s):
.... print(s) # type spaces or a tab instead of .... at the front
printme("Hello")
That's changed a bit. Your original version expected an argument and would have failed with "printme() expected 1 argument but found 0" or something like that, because the printme() call at the bottom didn't provide an argument.
The .... token is a substitute for a tab or spaces. Y!A removes "extra" spaces, so you can't paste code here and have it appear properly indented.
brilliant_moves
I agree with husoski. It depends on what the question is asking for. Another working solution would be:
def printme():
... print ("Hello")
printme()
Remember to use spaces or a tab instead of "... ".