math question?

The bus fare in a city is $ 1.75. People who use the bus have the option of purchasing a monthly coupon book for $28.00. With the coupon​ book, the fare is reduced to $0.75.Determine the number of times in a month the bus must be used so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book.

?2018-04-24T14:40:16Z

Favorite Answer

You save $1.00 on each fare if you have the $28.00 coupon book. With 28 rides, you've recouped the cost of the book.
Ans: 28 rides per month.

Raj K2018-04-24T15:22:00Z

Let x be the number of times the bus to be used so that the total
monthly cost with coupon and without coupon is same
Total cost for x times without coupon=$ 1.75 x
Total monthly cost with coupon is $ 28
hence $ 1.75 x=$28 or x=28/1.75=16 times

cmcsafe2018-04-24T15:03:04Z

1.

• n trips Cost for people without coupon book is equal to C = 1.75 * n
• n trips cost for people with coupon book is equal to c =28+ 0.75 * n


• Break even means C=c
1.75*n=28+ 0.75*n
1*n=28
n=28

The coupon book is convenient if you make a number of trips equal to or greater than 28.

below the graphic solution of the problem

Sunday Crone2018-04-24T14:45:51Z

28.00/.75=37. and 28.00/1.75 = 16 Very simple and basic math

GTB2018-04-24T14:26:33Z

n = number of bus trips to break even. 1.75n = 20.00 +0.75n; 1.00n = 20.00; n= 20.00/1.00 = 20