Como
3 x² - 18x + 27 = 3 [ x² - 6x + 9 ]
3 x² - 18x + 27 = 3 [ x - 3 ] ²
2x³ - 4x² - 6x = [ 2x ] [ x² - 2x - 3 ]
2x³ - 4x² - 6x = [ 2x ] [ x - 3 ] [ x + 1 ]
Krishnamurthy
The given polynomials:
3x^2 - 18x + 27 = 3(x^2 - 6x + 9) = 3(x - 3)^2
2x^3 - 4x^2 - 6x = 2x(x^2 - 2x - 3) = 2x(x - 3)(x + 1)
The LCM of the polynomials:
6x(x - 3)^2(x + 1) = 6 x^4 - 30 x^3 + 18 x^2 + 54 x
az_lender
3x^2 - 18x + 27 = 3(x^2 - 6x + 9) = 3(x-3)^2.
2x^3 - 4x^2 - 6x = (2x)(x^2 - 2x - 3) = (2x)(x-3)(x+1).
The LCM is (6x)(x+1)(x-3)^2 .
hayharbr
Factor each:
3(x^2 - 6x + 9) = 3(x - 3)(x - 3)
2x(x^2 - 2x - 3) = 2x (x - 3)(x + 1)
so you need a 3, a 2x, two (x - 3)'s and one (x + 1): 3•2x•(x - 3)(x - 3)(x + 1)
TicToc....
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