Puzzling
Let me ask you a question?
Is 0.333333... equal to 1/3 or is it *almost* 1/3?
Almost everyone can agree if you divide out 1/3, you get 0.333333... with an unending sequence of threes. The decimal representation of 1/3 is 0.333333... and both are equivalent. Very few people say that 0.333333... is *almost* 1/3. If they do, they are wrong.
However, when it comes to 0.999999... our intuition gets messed up and we can't make the same assertion. People start arguing that the value isn't exactly 1; that it's just a little smaller than 1 or *almost* 1. So why the different reasoning?
The fact is, just like 0.333333... is exactly 1/3, it's also true that 0.999999... is exactly 1.
0.333333... + 0.333333... + 0.333333... = 1/3 + 1/3 + 1/3
0.999999... = 1
Another pattern that might help; look at the fractions 1/9, 2/9, etc. written as decimals:
0.1111... = 1/9
0.2222... = 2/9
0.3333... = 3/9 (or 1/3)
0.4444... = 4/9
0.5555... = 5/9
0.6666... = 6/9 (or 2/3)
0.7777... = 7/9
0.8888... = 8/9
0.9999... = 9/9 (or 1)
Answer:
The value of 0.9999999... is exactly 1. You can think or imply that it is the number "just before 1" but it isn't.
geezer
EVENTUALLY
0.99999999999999999... will be so close to 1 that it will be 1
So .. to answer your question
If 0.9999999999999999... is 1
the number that ''follows'' 0.9999999999999999 (1) ... is 2
lenpol7
0.99999.... to infinity =
9/9
Cancel down = 1
K
Its less than one
But infinity doesnt exist in the real world
billrussell42
that is the same as 1.
If by number following, you mean next integer, that is 2