what is the temperature of the system (rod + water) at equilibrium assuming no losses to the surroundings?

Question

If a 136.51 g Al rod (c = 0.900 J/g°C) is at 100.0°C and placed into 250.0 g of water at 21.8°C, what is the temperature of the system (rod + water) at equilibrium assuming no losses to the surroundings?

2019-11-25T05:13:04Z

Help please. I'm not even sure where to begin.

Anonymous · Accepted Answer

energy given up by the hot Al = energy gained by the cold water

mass of Al * specific heat of Al * (100C - T) = mass of water * specific heat of water * (T - 21.8C)

T is the final temperature, solve for it.

RealPro · Answer

Well maybe you could begin with google since it's such a common, simple problem?

what is the temperature of the system (rod + water) at equilibrium assuming no losses to the surroundings?

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