A baseball (m =150 g) is traveling at 40.0 m/s how much work must be done to stop the ball?

Question

MyRank · Answer

Given,
Mass (m) = 150g = 0.15kg
Speed (v) = 40m/sec
Work (w) = ?
The work done will change into Kinetic Energy, when the ball brought to stop
So, work done (w) = Kinetic Energy (K.E) = ½mv²
Work done (w) = ½mv² = ½ x 0.15kg x (40m/sec)²
= ½ x 0.15kg x 1600m²/sec²
= 120Joules.

oubaas · Answer

W = KE = 0.15*40^2/2 = 800*0.15 = 120 joule

Mangal · Answer

Kinetic energy = ½mv² = ½(0.15 kg)(40 m/s)² = 300 J

300 J energy will be required to stop the baseball (then its KE will be 0)

Ans = 300 J

Anonymous · Answer

3.75

I'm not sure if my answer are is right

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A baseball (m =150 g) is traveling at 40.0 m/s how much work must be done to stop the ball?

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