When gravity bends light, does it effect all frequencies equally. Absolutely equally?

neb2020-06-05T16:22:23Z

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Yes. The geodesic equation - the path that something follows in spacetime free fall in a gravitational field - depends only on the local geometry of spacetime and the velocity. The velocity of light is independent of frequency and therefore all frequencies will follow the exactly the same geodesic. 

This ignores any infinitesimal gravity generated by the energy of the light itself (per Einsteins general relativity) since higher frequencies of light have more energy than lower frequencies of light. This would not be measureable in practice.

Ruel The Midianite2020-06-06T15:52:30Z

Well, if the wavelength is really long, comparable to the radius of curvature of space, the wave will diffract in a direction different from shorter waves.  But that's only for really long wavelength radio waves.

Tom2020-06-06T13:23:28Z

Equally, because it is the SPACE the light is traveling through that is being bent---Since all Light Frequencies travel in space in a straight line, we will see the entire BEAM bent the same despite it's frequency/s.  Light is not really being bent only the conduit (Space) that is carrying it.

Anonymous2020-06-06T04:30:16Z

Yeahhh : same treatment 

?2020-06-05T13:36:11Z

No. Actually electromagnetic waves have kinetic mass. Red light has very less mass than x rays and gamma rays. Therefore, guess work is gamma rays bend more than red light.

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