algebra II the revenue at a local restaurant increased by 4.2% over the previous year. if this trend continues, which expression shows their?

month percent increase in revenue? R(m) is the revenue and m represents months. 
a. R(m)=(1.042)^m
b. R(m)=(1.042)^12/m
c. R(m)=(1.00343)^m/12
d. R(m)=(1.00343)^m

Wayne DeguMan2020-11-13T10:34:21Z

An increase of 4.2% per year in revenue can be expressed as:

R(year) = 1.042

so, monthly this is (1.042)¹/¹² => 1.003434379

Hence, over m months we can say:

R(m) = (1.00343)ᵐ

:)>

Alan2020-11-13T07:28:25Z

so you're 1st statement means 
R(y) = (1.042)^(y)  
since y = (m/12)  
then 
R(m) = (1.042)^(m/12)   
since that is not  an option we go forward
However, we know that answers "a" and "b" 
are wrong unless you made a typo 
so either  
(1  +  0.00343)^(m/12) =  (1.042)^(m/12) 
(1.00343)^(m/12) = (1.042)^(m/12)  
but that means  1.00343  = 1.042 
but it doesn't  
so by process of elimination 

d. R(m)=(1.00343)^m
is correct 

why is that correct?
take 
(1,042)^(m/12) = (1.042^(1/12))^(m)  
(1.042^(1/12) ) ^m   = (1.00343)^m