6N force pushes to the right on a 3 kg mass for 8 seconds. How much momentum was gained?

48kg*m/s

2kg*m/s

0.5kg*m/s

or 0kg*m/s

az_lender2021-02-15T04:31:44Z

Favorite Answer

a = 2 m/s^2, 
delta-v = 16 m/s,
delta-p = 48 kg*m/s.

OR:  F = delta-p/delta-t =>
delta-p = F delta-t = (6N)/(8 s) = 48 kg*m/s

20

Demiurge422021-02-16T02:05:59Z

There's not enough information  to determie how much momentum was gained.  It could even be losing momentum.

00

oubaas2021-02-15T06:22:11Z

ΔP = ΔI = 6 N * 8 sec = 48 N*sec = 48 kg*m/sec 
ΔV = ΔP / m = 48 kg*m/sec / 3 kg = 16 m/sec 

30

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