Raymond
Favorite Answer
There is another way to write the same equation (looks different - carries the exact same information).
It is called the "slope-intercept" format, and it looks like this:
y = mx + c
where m and c are (normally) just numbers:
m is the slope (how fast y rises, when x rises by 1, and
c is the y-intercept (the value of y, when x=0)
Use the normal rules of equation manipulation to get there, from here:
2x - 3y = 18
multiply both sides (all terms) by -1
-2x + 3y = -18
add "2x" to both sides
3y = 2x - 18
divide both sides by 3
y = (2/3)x - 6
the slope = 2/3
the y-intercept = -6
To check, make x=0 and solve for y
y = (2/3)(0) - 6
y = -6
Krishnamurthy
2x - 3y = 18
line
x-intercept | 9
y-intercept | -6
normal vector | (-2/sqrt(13), 3/sqrt(13))≈(-0.5547, 0.83205)
slope | 2/3≈0.666667
curvature | 0
?
2x - 3y = 18
You need to know that the y-intercept is where the graph crosses the y axis.
The y axis is the line where x = 0, so substituting that gives
2*0 - 3y = 18
y = -6
az_lender
When x = 0, the y = -6.
Answer: -6