Find the equation of the tangent line to the parametric curve at t=2?
x = 1/(t+1)
y = t/(t-1)
x = 1/(t+1)
y = t/(t-1)
?
Two ways:
1) express y = y(x). That's high school algebra. Show your answer here as an update to your post. Then we will take it from there.
2) TBC...
Hopefully no one will spoil you the answer. That would be very irresponsible of them.
Bryce
x'= -1/(t+1)², y'= -1/(t-1)²
dy/dx= (t+1)²/(t-1)²
At t= 2, dy/dx= 9
At t= 2, (1/3, 2)
y= 9(x - 1/3) + 2