How many 1.50-L balloons can be completely filled with 0.603 moles of helium gas at STP?

Roger the Mole2021-03-16T18:30:09Z

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Supposing STP to be 1 atm and 0°C:
(0.603 mol) x (22.414 L/mol) / (1.50 L / balloon) = 9 balloons

Jim2021-03-16T18:31:20Z

PV=nRT <<<memorize!!
n is moles, R is gas constant (use correct one!), T is temp in K (C+273.15)
Since you have a before and after with the same n &R simplifies to
PV/T initial = nR = PV/T final
Now sub in your numbers and solve
SI Units R values:
8.31446261815324 J⋅K−1⋅mol−1
8.31446261815324 m3⋅Pa⋅K−1⋅mol−1
8.31446261815324 kg⋅m2·K−1⋅mol−1s−2
8.31446261815324×103 L⋅Pa⋅K−1⋅mol−1
8.31446261815324×10−2 L⋅bar⋅K−1⋅mol−1
0.082057 L atm mol-1K-1
62.36L·torr/mol·K = L·mmHg/mol·K

US Customary Units R values:
0.730240507295273 atm⋅ft3⋅lbmol-1°R-1
10.731557089016 psi⋅ft3⋅lbmol-1°R-1
1.985875279009 BTU⋅lbmol-1°Rv-1