1. How many atoms are there in 24 grams of calcium? 2. What is the mass of one mole of calcium carbonate, CaCO3? will provide Fave answer?

Favorite Answer

1.
(24 g Ca) / (40.0784 g Ca/mol) x (6.022 x 10^23 atoms/mol) = 3.6 × 10^23 atoms Ca

2.
CaCO3 = 100.0875 g/mol

3. A)
CH4O = 32.0419 g/mol
H4 = 4.03176 g/mol
(4.03176 g/mol) / (32.0419 g/mol) = 0.125827 = 12.5827% H by mass

3. B)
C2H5OH = 46.0684 g/mol
H6 = 6.04764 g/mol
(6.04764 g/mol) / (46.0684 g/mol) = 0.131275 = 13.1275% H by mass

3. C)
C3H6O = 58.0791
(6.04764 g/mol) / (58.0791 g/mol) = 0.104128 = 10.4127% H by mass

So in decreasing order of %H:
C2H5OH
CH4O
C3H6O...Show more