?
So you have a pyramid of height 2 sitting on top of the frustum. The volume of the large pyramid is (1/3)(6)(s^2) and the volume of the small pyramid is (1/3)(2)(s/3)^2;
the ratio of the volume of the large pyramid to the small pyramid is 6/(2/9) = 27.
The volume of the frustum is 26/27 of the volume of the large pyramid.