Reaction: 2 ICl + H2 I2 + 2 HCl (all gases)?

Question

Reaction: 2 ICl + H2 I2 + 2 HCl (all gases)
Experimental results: The rate is halved when [ICl] x ½
The rate triples when [H2] x 3
a) What is the order in each reactant?
b) What is the rate law?
c) What is the overall order?
d) By what factor will the rate change if both [ICl] and [H2] are doubled?
e) By what factor will the rate change if [ICl] is tripled and [H2] is cut x ¼?
f) What are the units for the rate constant k?

Bobby · Answer

The rate is halved when [ICl] x ½ so the rate is proportional to [ICI] . first order
if the rate triples when [H2] x 3 the rate is proportional to [H2] . first order

rate = k [ICl] * [H2]

overall order is 1+1 = second order

if both [ICl] and [H2] are doubled the rate * 4

if [ICl] is tripled and [H2] is cut x ¼  rate * 3/4

unit of k are :
mole/ liter / sec = k * mole^2 Liter ^-2
k = mole^1* liter ^-1 *sec^-1  * mole^-2 *Liter ^2 = mol-1 liter sec^-1

Reaction: 2 ICl + H2 I2 + 2 HCl (all gases)?

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