How many grams of oxygen gas are produced when 2.43 x 10⁻⁴ g of KClO₃ are completely reacted according to the following chemical equation:

2KClO₃ (s) → 2KCl (s) + 3 O₂ (g)

Question

How many grams of oxygen gas are produced when 2.43 x 10⁻⁴ g of KClO₃ are completely reacted according to the following chemical equation:

2KClO₃ (s) → 2KCl (s) + 3 O₂ (g)

Roger the Mole · Answer

(2.43 × 10^-4 g KClO₃) / (122.5495 g KClO₃/mol) × (3 mol O₂ / 2 mol KClO₃) ×
(31.99886 g O₂/mol) = 9.52 × 10^-5 g

How many grams of oxygen gas are produced when 2.43 x 10⁻⁴ g of KClO₃ are completely reacted according to the following chemical equation:?