Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.?

Question

Specific heat values:
Water: 4.184 J/g &#92;cdot⋅ degrees Celsius

Ice= 2.0g J/g &#92;cdot⋅ degrees Celsius

Steam= 2.02 J/g &#92;cdot⋅ degrees Celsius

Heat of fusion= 334.72 J/g

Heat of vaporization = 2259.36 J/g &#92;cdot⋅

**NO ANSWER CHOICES PROVIDED**

hcbiochem · Answer

You will do 3 calculations and add their results together:

a) heat to raise the temp of the water from 35.0 C to 100 C:
q = m c (T2-T1)
q = 10.0 g (4.184 J/gC) (100 - 35.0 C) = 2720 J

b) heat to vaporize the water:
q = m (heat of vaporization)
q = 10.0 g (2259.36 J/g) = 22594 J

c) heat to raise temp of steam to 110 C:
q = m c (T2-T1)
q = 10.0 g (2.02 J/gC) (110-100 C) = 202 J

qtotal = 2.55X10^4 J = 25.5 kJ

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