A buffer solution is prepared by mixing 25.0 mL of 2.45 M HF and 22.0 mL of 1.45 M NaF. Determine the pH of the buffer. Ka HF = 6.80E-4?

find the initial [HF] and [NaF] in the mixture - treat each as a dilution using M1V1=M2V2

i.e. for HF

2.45 x 25.0 = M2 x (25.0 + 22.0) and solve for M2 = [HF]

do the same for NaF

then use the HH equation

pH = pKa + log([NaF]/[HF])...Show more