A water molecule (MM = 0.0180 kg/ = mole) has a kinetic energy of 6.44x10^21 J. What is its temperature?

Shouldn't the kinetic energy be 6.44X10^-21 J?

The average kinetic energy of any gas is directly related to the absolute temperature by:

KE = 3/2 (k) T
k = Boltzmann constant which is R/NA (Avogadro's number

So, 6.44X10^-21 J = 3/2 (8.314 J/molK/ 6.022X10^23) T
T = 311 K ...Show more