A 1300kg sack of coal is dropped on a 2000kg railroad flatcar which was initially moving at 3 m/s as shown. ?

 After the sack rest on the flatcar, the speed of the flatcar is?

NCS2021-04-08T02:45:58Z

v = 3m/s * 2000/(2000+1300) = 1.8 m/s

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