How many mL of 0.284 M KOH are needed to react completely with 35.0 mL of 0.155 M sulfuric acid?

a. 38.2 mL

b. 19.1 mL

c. 25.3 mL

d. 32.1 mL

Question

How many mL of 0.284 M KOH are needed to react completely with 35.0 mL of 0.155 M sulfuric acid?
  
a. 38.2 mL
   
b. 19.1 mL
   
c. 25.3 mL
   
d. 32.1 mL

Roger the Mole · Answer

H2SO4 + 2 KOH → K2SO4 + 2 H2O

(35.0 mL) x (0.155 M H2SO4) x (2 mol KOH / 1 mol H2SO4) / (0.284 M KOH) =
38.2 mL KOH

So answer a.

How many mL of 0.284 M KOH are needed to react completely with 35.0 mL of 0.155 M sulfuric acid?

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