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katrina sent a 10kg box down a flight of stairs. The box fell a vertical distance of 3 meters and had a velocity of 4 m/s at the bottom of the stairs
How much gravitational potential energy did the the box loose by the the time it reached the bottom of the stairs?
1 Answer
- Anonymous1 decade agoFavorite Answer
gravitational potential energy(GE) = mhg, where m is the mass, h is the height and g is the gravitational constant on earth. The standardized unit for energy is the Joule, which requires mass to be in kg, height to be in metres and g to be in metres per second squared. The gravitational constant on earth is -9.8m/s^2. THe negative means that gravity pulls down, and can be ignored here. In this case, mass = 10kg, height = 3m. Henceforth, gravitational potential energy lost is: mgh=10kg*3m*9.8m/s^2=240joules.
From how you stated the question, however, it sounds like you were actually looking for the gravitational potential energy that was not transformed into kinetic energy, in math terms GE-KE. We already know GE. KE or kinetic energy is equal to (1/2)mv^2, where m is mass and v is velocity(a concept similar to speed but with a sense of direction). To retain an answer in joules once again, v must be in m/s and m must be in kg. In your case m=10kg and v=4m/s. plug this in: KE=(1/2)*10kg*(4m/s)^2=80Joules. This makes GE -KE = 240- 80 = 160Joules lost.
Source(s): Conceptual Physics by Kinetic Books