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a 4kg box slides across a table to the righ twitha velocity of 0.1 m/s. If a 5 N force to the right and a 0.5 N force of friction to the left act on a box. what happens to its momentum>
6 Answers
- 1 decade agoFavorite Answer
It will increase, the initial momentum is p=mv or 4*.1=.4 kg*m/s, the box has a net force of 4.5 N to the right, any positive net force will cause the box to accelerate, in this case since f=ma, the box will accelerate at a rate of 4.5N/4kg, or 1.125 m/s^2. Every second, the box will increase it's speed by 1.125 m/s, so the box's momentum will also increase according to the equation p=mv. If we wanted to model the momentum of the box with an equation, we would use p=4*(.1+(1.125*t)), where t is time in seconds starting at 0.
- Anonymous1 decade ago
the wiegh on the right would be heavier and it wouldnt balanced
- Anonymous1 decade ago
OMG i have the same question are u in my class