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Condensing logarithms ?
How would you condense this into a single quantity
6[ln(x) – ln (x + 3) – ln (x – 3)]
2 Answers
- allen sLv 51 decade agoFavorite Answer
6[ln(x) – ln(x + 3) – ln(x – 3)] --->
6[ln(x) – ln(x + 3) – ln(x – 3)] = 6[ln(x) – {ln(x + 3) + ln(x – 3)}]
6[ln(x) – {ln(x + 3) + ln(x – 3)}] = 6[ln(x) – ln{(x + 3)(x – 3)}]
6[ln(x) – ln{(x + 3)(x – 3)}] = 6[ln(x) – ln(x^2 - 9)]
6[ln(x) – ln(x^2 - 9)] = 6 ln[x/(x^2 - 9)] = ln[x/(x^2 - 9)]^6
- 1 decade ago
ln(a) + ln(b) = ln(axb)
ln(a) - ln(b) = ln(a/b)
6[ln(x) – {ln (x + 3) + ln (x – 3) } ]
6 [ ln(x) - ln{ (x+3)X(x-3) } ]
6 [ ln(x) - ln(x^2- 9) ]
6 ln { x / (x^2- 9) }
Good Luck ;)