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I can't seem to remember the formula for this geometry problem...?

I was given a circle, and out of that circle was-excuse my lack of terminology- a piece of "pie" cut out. The sides of the angle drawn both had a length of 12, and the outside arc of the circle, between the two "cuts" made, was 16 inches.

So, in short; a pie piece, the sides of which are 12 inches, both, and the "crust" of which measures 16 inches. Now, I'm wondering how big the angle I cut at the center of the pie was. Anybody know that formula? D=

Update:

Thanks so much guys! That was very promt, and they're all great explanations. <3

7 Answers

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  • 1 decade ago
    Favorite Answer

    Yes. Let me explain.

    The radius is given to you as r=12.

    The total circumference of the pie should be:

    2πr = 24π ≈ 75.4

    Now, what you have done is subtracted 16 from that.

    What percentage have you subtracted?

    16 / 75.4 = 21.22%

    You have also removed that amount of the 360° angle around the center of the pie. In other words, the angle you removed is:

    (21.22%) × 360° = 0.2212 × 360° = 76.4°

    That's your answer.

    Note: The similarity between circumference (75.4) and the angle (76.4°) is a complete coincidence.

  • 1 decade ago

    The formula for the circumference of a circle (the "crust" as you call it) is:

    C = 2π r

    r is the radius, which in your case is 12 inches. So the total circumference would be:

    C = 2π * 12

    = 24π

    ≈ 75.4 inches

    You have a section of the circumference that is only 16 inches.

    Similarly, your angle will only be part of the full 360°

    These two ratios will be the same:

    16 to 75.4 (arc to full circumference)

    x to 360° (angle to full circle)

    Equate them:

    16/75.4 = x/360°

    Simplify the left hand side:

    0.2122 = x/360°

    Multiply both sides by 360°

    x = 0.2122 * 360°

    x ≈ 76.4°

  • 1 decade ago

    What you are describing is a sector of the complete circle, and the info given to you are:

    radius = r = 12

    arc = s= 16

    The formula to find the angle is

    s= r * tetha

    Being tetha the angle given in radians. So lets find that:

    tetha= s/r= 16/12= 1.33 radians.

    Now we use conversions to find the angle in degrees:

    1.33 radians * ( 360 degrees/ 2 pi radians) = 76.4 degrees.

    Thats all

    ANSWER

  • 1 decade ago

    I think the "sides" you are referring to are the radii (singular form: radius). The 16 inches you are talking about is the arc length (the circumference) excluding the radii.

    The basic foruma for getting the circumference (C) is

    2(pi)(r); pi is the ratio of the circumference to the diameter and is approximately equal to 3.14.

    The arc length is like a pro-rated circumference. If x is the angle of the arc, then

    C of arc = 2(pi)(r)(x/360)

    16 = 2 (pi) (12) (x/360)

    x=((8)(360))/((12)(pi))

    x=((360)2)/((3)(pi))

    x=720/((3)(pi))

    x=240/pi

    If we convert it to decimal, the angle is approximately 76.43 degrees.

  • Pointy
    Lv 7
    1 decade ago

    Crust length = Side length * Θ

    where

    Crust length = 16

    Side length = 12

    Θ = angle of pie cut (in radians)

    Substituting values,

    16 = 12(Θ)

    Θ = 16/12 = 4/3 radians

    and since there are 180 degrees per π radians, then

    Θ = (4/3)(180/π)

    Θ = 76.39 degrees

    Hope this helps.

  • 1 decade ago

    I'll answer the question because it is too hard to explain...

    You take the side measured 12 (Radius) and find the circumference.

    C=2•3.14•12= 75.36

    Here is the formula: arc length = angle/360 • C

    16 = angle/360 • 75.36

    Divide 75.36 to each side to get:

    0.2123 = angle/360

    Multiply 360 to each side to get:

    76.4 = angle

    There's your answer.

    ii

  • Como
    Lv 7
    1 decade ago

    Circumference of whole pie = 2 π r = 24 π ins

    Length of arc = 16 ins

    24 π<------------>360°

    16 <-------------->16/(24 π) x 360°

    2 / (3π) x 360° = 76.4°

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