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Math help pleaseeeee?

Multiply. (3z-1) and (z-4)

Update:

Divide. 9.25 x 10^8 and 2.5 x 10^3 express in scientific notation

Update 2:

Divide. 9.25 x 10^8 and 2.5 x 10^3 express in scientific notation

11 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Use FOIL method: Multiply First term,Outer,Inner,and Last term.

    (3z-1) (z-4) = 3z^2 - 12z - z + 4

    (then,combine the like terms:)

    = 3z^2 - 13z + 4

  • 1 decade ago

    Remember FOIL:

    First, Outside, Inside, Last

    (3z-1)(z-4)

    = (3z*z) + (-1*z) + (3z*-4) + (-4*-1)

    =3z^2-1z-12z+4

    = 3z^2-13z+4

  • 1 decade ago

    (3z-1)(z-4)

    =3z*z - 3z*4 - 1*z + 1*4

    =3z^2 - 12z - z + 4

    = 3z^2 - 13z + 4

  • Anonymous
    1 decade ago

    3z^2 -12z -z +4

    3z^2 -13z +4

  • Dee W
    Lv 7
    1 decade ago

    3z^2 - 13z + 4

  • 1 decade ago

    3z^2+11z+4

  • Anonymous
    1 decade ago

    3z x z = 3z^2

    3z x 4 = 12z

    -1 x z = -z

    -1 x -4 = 4

    So put them all together and you get..

    3z^2 + 4 +11z

    .....

    The other answers are wrong btw. From the other people.

  • 1 decade ago

    3z^2-13z+4

  • Anonymous
    1 decade ago

    1.) 3z^2-13z+4

    2.) 3.7E5

  • HPV
    Lv 7
    1 decade ago

    (3z - 1)(z - 4) = (3z)(z) + (3z)(-4) + (-1)(z) + (-1)(-4) = 3z^2 - 12z - z + 4 = 3z^2 -13z + 4

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