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Balanced chem equation?

Is 2 Fe + 3O ...... Fe2O3

9 Answers

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  • 1 decade ago
    Favorite Answer

    Please remember that oxygen is diatomic. Oxygen = O2.

    4Fe(s) + 3O2(g) --> 2Fe2O3(s)

    By the way, this is not the equation for the formation of "rust". The reaction to form rust REQUIRES water.

    Rust is FeO(OH), at least is in in normal environments.

    4Fe(s) + 3O2(g) + 2H2O(l) --> 4FeO(OH)(s)

    Fe(OH)3 = rust which forms in water

    FeO(OH) = "normal" rust

    Fe2O3 = rust which has "dried out"

  • Well, since oxygen is a diatomic molecule... This equation becomes...

    4Fe + 3O2 --> 2Fe2O3

    Source(s): I'm an AP Chemistry Student
  • 1 decade ago

    No, it's not. You should not change the subscripts of the substances when you balance a chemical equation. Changing the subscripts changes the substances' identity.

    Oxygen always exists in the diatomic form O2, unless stated otherwise. So the new balanced equation should be

    4Fe + 3O2 --> 2Fe2O3

    Happy New Year!

    :)

  • Anonymous
    1 decade ago

    It is 4 Fe + 3O2 => 2Fe2O3

    because oxygen is diatomic in this case

  • 1 decade ago

    Mathematically, yes. It is balanced.

    Unless this is a net Ionic equation, (If you don't know if it is or not, then it probably isn't) then pure Oxygen will exist only as O2 or O3. It cannot just be O, because oxygen has a charge of -2.

    hope this helps.

    Source(s): college level chemistry.
  • Anonymous
    1 decade ago

    yes, except ur 3O is wrong. O2 is what is normally found...

  • Dr.A
    Lv 7
    1 decade ago

    No because O exists as O2 ( diatomic molecule)

    so the balanced equation is :

    4 Fe + 3 O2 >> 2 Fe2O3

  • 1 decade ago

    Yes. You start out with 2 iron atoms and end up with two, start with 3 oxygen and end up with 3.

  • vivier
    Lv 4
    5 years ago

    2AgNo3 + K2CrO4 = Ag2CrO4 +2KNO3 The valence or combining capability of ok is a million and so is that of NO3. you are able to continually build the suitable formulae of the products earlier you attempt to stability the form of molecules. (ie the form in front of each molecule.

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